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authorPaul Eggleton <paul.eggleton@linux.intel.com>2016-01-07 00:15:49 +1300
committerRichard Purdie <richard.purdie@linuxfoundation.org>2016-01-11 15:41:06 +0000
commit64986decbc11afa0d1e11251f5f7adcba1860d19 (patch)
tree6dc3058964e63a46debf5a611efcb38884f0b4f7 /scripts/lib
parent0bba4b5afd2ce2c3a79445eee886979a77f1a4d8 (diff)
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recipetool: create: lower case name when determining from filename
As a matter of general convention we expect recipe names to be lower case; in fact some of the packaging backends insist upon it. Since in this part of the code we're auto-determining the name, we should convert the name to lowercase if it's not already so that we're following convention and avoiding any validation issues later on. Signed-off-by: Paul Eggleton <paul.eggleton@linux.intel.com> Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>
Diffstat (limited to 'scripts/lib')
-rw-r--r--scripts/lib/recipetool/create.py4
1 files changed, 2 insertions, 2 deletions
diff --git a/scripts/lib/recipetool/create.py b/scripts/lib/recipetool/create.py
index 873b7ddcc6..f3428577b9 100644
--- a/scripts/lib/recipetool/create.py
+++ b/scripts/lib/recipetool/create.py
@@ -90,9 +90,9 @@ def determine_from_filename(srcfile):
"""Determine name and version from a filename"""
part = ''
if '.tar.' in srcfile:
- namepart = srcfile.split('.tar.')[0]
+ namepart = srcfile.split('.tar.')[0].lower()
else:
- namepart = os.path.splitext(srcfile)[0]
+ namepart = os.path.splitext(srcfile)[0].lower()
splitval = namepart.rsplit('_', 1)
if len(splitval) == 1:
splitval = namepart.rsplit('-', 1)